Riddle: 3 men are renting a hotel room. The Manager tells the men that the price is $30.00. The 3 men split the cost and pay $10.00 each. Later that night, the manager realizes he made a mistake, the room was only $25.00. The manager then calls over the Bell Boy and gives him 5 $1.00 bills and asks him to return it to the 3 men. On the way to the room the Bell Boy can not figure out how he is going to split the $5.00 evenly between the 3 men. Just as the Bell Boy reaches the door, he decides that he will give each man $1.00 and put the other $2.00 in his pocket.
With that in mind lets do the math.
The 3 men paid $10.00 each for a total of $30.00
The manager made a mistake and gave the Bell Boy $5.00 to return to the men.
The Bell Boy gave each man $1.00 back and kept $2.00 for himself.
If each man recieved $1.00 back then they would have paid $9.00 each.
$9.00 times 3 men equals $27.00, plus the $2.00 the Bell Boy kept equals $29.00.
If the 3 men originally paid $30.00, where is the other dollar?
Answer: The answer is simple,
The original amount is a base of $30.00 the 3 men split the cost and paid $10.00 each.
3 x $10.00 = $30.00
The riddle however switches the base amount from $30.00 to $25.00 because of the refund.
$30.00 - $5.00 = $25.00
Now lets do the math.
3 men paid $9.00 each making the total $27.00 dollars.
3 x $9.00 = $27.00
Minus the $2.00 the Bell Boy kept equals the new base of $25.00 dollars.
$27.00 - $2.00 = $25.00
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